128=16t^2+32t

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Solution for 128=16t^2+32t equation:


Simplifying
128 = 16t2 + 32t

Reorder the terms:
128 = 32t + 16t2

Solving
128 = 32t + 16t2

Solving for variable 't'.

Reorder the terms:
128 + -32t + -16t2 = 32t + -32t + 16t2 + -16t2

Combine like terms: 32t + -32t = 0
128 + -32t + -16t2 = 0 + 16t2 + -16t2
128 + -32t + -16t2 = 16t2 + -16t2

Combine like terms: 16t2 + -16t2 = 0
128 + -32t + -16t2 = 0

Factor out the Greatest Common Factor (GCF), '16'.
16(8 + -2t + -1t2) = 0

Factor a trinomial.
16((2 + -1t)(4 + t)) = 0

Ignore the factor 16.

Subproblem 1

Set the factor '(2 + -1t)' equal to zero and attempt to solve: Simplifying 2 + -1t = 0 Solving 2 + -1t = 0 Move all terms containing t to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1t = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1t = 0 + -2 -1t = 0 + -2 Combine like terms: 0 + -2 = -2 -1t = -2 Divide each side by '-1'. t = 2 Simplifying t = 2

Subproblem 2

Set the factor '(4 + t)' equal to zero and attempt to solve: Simplifying 4 + t = 0 Solving 4 + t = 0 Move all terms containing t to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + t = 0 + -4 Combine like terms: 4 + -4 = 0 0 + t = 0 + -4 t = 0 + -4 Combine like terms: 0 + -4 = -4 t = -4 Simplifying t = -4

Solution

t = {2, -4}

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